changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Jan 11, 2021
...
Volumetric Flowrate in inclined pipe: LaTeX Math Inlinebody\cos \theta \neq 0
q_0^2 = \frac{2 d A^2 G}{f} \cdot \left[ 1 + \frac{ (\rho/\rho_0)^2 -1}{1- (\rho_0/\rho_0)^{\frac{2}{n-1}} \cdot \exp \left( \frac{fL/d}{ n-1} \right)} \right]
Volumetric Flowrate in horizontal pipe: LaTeX Math Inlinebody\cos \theta = 0
q_0^2 = \frac{A^2}{c^* \rho^*} \cdot \frac{1 - (\rho/\rho_0)^2}{2 \ln (\rho_0/\rho) + fL/d}