changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Jan 10, 2021
...
q_0^2 = \frac{A^2}{c^* \rho^*} \cdot \frac{1 - (\rho/\rho_0)^2 \cdot \exp \left( -L/ L^* \right)}{2 \ln (\rho_0/\rho) + fL/d \cdot (1- \exp \left( - L/ L^* \right))/(L/L^*)}
\dot m^2 = \frac{A^2}{c^* \rho^*} \cdot \frac{\rho_0^2 - \rho^2 \cdot \exp \left( -L/ L^* \right)}{2 \ln (\rho_0/\rho) + fL/d \cdot (1- \exp \left( - L/ L^* \right))/(L/L^*)}
\rho = \rho_0 \, \exp (2 \, L/L^*) \cdot \sqrt{ 1 - \frac{f}{2d} \cdot \frac{j_m^2}{G \, \rho_0^2} \cdot ( 1 - \exp(-L/L^*)}
p(L) = \frac{1}{c^*} \cdot \left[ -1 + (\rho^*/\rho_0/\rho^*) \cdot \exp (2 \, L/L^*) \cdot \sqrt{ 1 - \frac{f}{2d} \cdot \frac{j_m^2}{G \rho_0^2} \cdot \left(1 - \exp (-L/L^*) \right) } \right]
\rho = \rho_0 \, \exp (L/L^*)
p(L) = \frac{-1 + (\rho^*/\rho_0/\rho^*) \cdot \exp(L/L^*)}{c^*}