changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Jun 14, 2020
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F(p, l)=\left( \frac{1}{\rho^2} - \frac{1}{\rho_0^2} \right) + \left( \frac{f}{\rho^2} + \frac{f_0}{\rho_0^2} \right) \cdot \frac{l}{ 2 \, d} - (2/j_m^2) \, \int_p^{p_0} \frac{dp}{\rho} - (2/j_m^2) \, g \, \Delta z(l) = 0
\dot m = A \cdot \sqrt{ 2 \cdot \frac { g \, \Delta z + \int_p^{p_0} \frac{dp}{\rho} } { \left( \frac{1}{\rho^2} - \frac{1}{\rho_0^2} \right) + \left( \frac{f}{\rho^2} + \frac{f_0}{\rho_0^2} \right) \cdot \frac{l}{ 2 \, d} } }
Volumetric Intake Volumetric Flowrate
q_0 = \frac{A}{\rho_s} \cdot \sqrt{ 2 \cdot \frac { g \, \Delta z + \int_p^{p_0} \frac{dp}{\rho} } { \left( \frac{1}{\rho^2} - \frac{1}{\rho_0^2} \right) + \left( \frac{f}{\rho^2} + \frac{f_0}{\rho_0^2} \right) \cdot \frac{l}{ 2 \, d} } }
j_m = \sqrt{ 2 \cdot \frac { g \, \Delta z + \int_p^{p_0} \frac{dp}{\rho} } { \left( \frac{1}{\rho^2} - \frac{1}{\rho_0^2} \right) + \left( \frac{f}{\rho^2} + \frac{f_0}{\rho_0^2} \right) \cdot \frac{l}{ 2 \, d} } }