changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Nov 04, 2019
...
\bigg( 1 - \frac{c(p) \, \rho_0^2 \, q_0^2}{A^2} \bigg ) \frac{dp}{dl} = \rho(p) \, g \, \frac{dz}{dl} - \frac{\rho_0^2 \, q_0^2 }{2 A^2 d} \frac{f({\rm Re}, \, \epsilon)}{\rho(p)}
uq(l) = \frac{\rho_0 \cdot q_0}{\rho(p) \cdot A}
qu(l) = \frac{\rho_0 \cdot q_0}{\rho(p) \cdot A}
p(l=0) = p_0
q(l=0) = q_0
where
characteristic linear dimension of the pipe
(or exactly a pipe diameter in case of a circular pipe)