$//<![CDATA[ \begin{array}{l}\displaystyle \mu_o(p, T) = \mu_{ob} + 1.3449E-3 \cdot ( p - p_b) \cdot 10^A\end{array} //]]>$
$//<![CDATA[ \begin{array}{l}A = c1 + c2 \cdot \log(\mu_{ob}) + c3 \cdot \big[ \log(\mu_{ob}) \big]^2 + c4 \cdot \left[ \log(\mu_{ob}) \right]^3\end{array} //]]>$
$//<![CDATA[ \begin{array}{l}c_1 = -1.0146, \ c_2 = 1.3322 \ c_3 = -0.4876, \ c_4 = - 1.15036, c_5 =1.3449 \cdot 10^{-3}\end{array} //]]>$