$//<![CDATA[ \begin{array}{l}\displaystyle \log_{10}(p_b) = 1.7669 + 1.7447 \, \log_{10}(p^*_b) - 0.30218 \, [\log_{10}(p^*_b) ]^2\end{array} //]]>$, $//<![CDATA[ \begin{array}{l}\displaystyle p^*_b = \left( R_{sb}/\gamma_g \right)^{c_1} \, T^{c_2} \, \gamma_{API}^{c_3}\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}\mbox{Black Oil: } c_1 = 0.816, \ c_2 = 0.172, \ c_3 = -0.989\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}\mbox{Volatile Oil: } c_1 = 0.816, \ c_2 = 0.130, \ c_3 = -0.989\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}\displaystyle R_s(p, T) = \gamma_g \cdot \big[ \gamma_{API}^{0.989} \, p^*_b \, T^{-0.172} \big]^{1.2255}, \quad p^*_b = 10^X, \quad X = 2.8869 - (14.1811 - 3.3093 \, \log_{10} p)^{0.5}\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}\displaystyle B_o(p, T) = 1.0 + 10^A, \quad A = c_1 + c_3 \, \log_{10} B^*_{ob} + c_3 \, \left( \log_{10} B^*_{ob} \right)^2\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}B^*_{ob} = R_s(p, T) \, \left( \frac{\gamma_g}{\gamma_o} \right)^{c_4} + c_5 \, T\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}c_1 = -6.58511, \ c_2 = 2.91329, \ c_3 = 0.27683, \ c_4 =0.526, \ c_6 = 0.968\end{array} //]]>$