$//<![CDATA[ \begin{array}{l}\displaystyle B_o(p) = c_1 + c_2 \cdot \left[ R_s(p) \left( \frac{\gamma_g}{\gamma_o} \right)^{c_4} + c_3 \, T \right]^{c_5}\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}c_1 = 0.972, \ c_2 = 1.47 \cdot 10^{-4}, \ c_3 = 1.25, \ c_4 = 0.5, \ c_5 = 1.175\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}\displaystyle R_s(p) = \gamma_g \cdot \big[ (c_1 +c_2\, p) \cdot 10^X \big]^{c_3}, \quad X = c_4 \, \gamma_{API} + c_5 \, T\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}c_1 = 1.4, \ c_2 = 1/18.2, \ c_3 = 1.2048, \ c_4 = 0.0125, \ c_5 = -0.00091\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}\displaystyle p_b = c_1 \cdot \left[ \left( \frac{R_{sb}}{\gamma_g} \right)^{c_2} \, 10^{-X }+ c_3 \right], \quad X = c_4 \, \gamma_{API} + c_5 \, T\end{array} //]]>$

$//<![CDATA[ \begin{array}{l}c_1 = 18.2, \ c_2 = 0.83, \ c_3 = -1.4 \ c_4 = 0.0125, \ c_5 = -0.00091\end{array} //]]>$