changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Jul 24, 2020
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\left( 1 - j_m^2 \cdot \frac{c}{\rho} \right ) \frac{dp}{dl} = \rho \, g \, \frac{dz}{dl} - \frac{j_m^2 }{2 d} \cdot \frac{f(p)}{\rho}
j_m = \frac{\rho_0 \cdot q_0}{\rho_0 \cdot A}
Alternative form:
\left[ \frac{1}{c} - \frac{j_m^2}{\rho} \right] \cdot \frac{d \rho}{dl} = \rho^2 \, g \, \cos \theta - \frac{j_m^2 }{2d} \cdot f(\rho)