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LaTeX Math Block
alignmentleft
\begin{cases}

\displaystyle 

{\frac {d{\vec {x}}_{P}}{dt}}(t)={\vec {u}}_{P}({\vec {x}}_{P}(t),t)
\\[1.2ex]

{\vec {x}}_{P}(t_{0})={\vec {x}}_{P0}

\end{cases}

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