changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Feb 07, 2019
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\frac{d Q^{\downarrow}_{AQ}}{dt_D} = \frac{ B \cdot (p_i - p(t_D)) - Q^{\downarrow}_{AQ} \cdot p'_D(t)}{p_D(t) - t \cdot p'_D(t)}
q^{\downarrow}_{AQ}(t)=\frac{d Q^{\downarrow}_{AQ}}{dt}
p_D= \frac{370.529 \, \sqrt{t_D} +137.528 \, t_D + 5.69549 \, t_D^{1.5}} {328.834 +265.488 \, \sqrt{t_D} + 45.2157 \, t_D + t_D^{1.5} }
p'_D= \frac {716.441 + 46.7984 \, \sqrt{t_D} + 270.038 \, t_D + 71.0098 \, t_D^{1.5} } { 1296.86 \, \sqrt{t_D} + 1204.73 \, t_D + 618.618 \, t_D^{1.5} + 538.072 \, t_D^2 + 142.41 \, t_D^{2.5} }
t_D= \frac{\pi \, \chi \, t}{A_e}