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LaTeX Math Block
alignmentleft
\begin{cases}

\displaystyle 

{\frac {d{\vec {r}}_s(t)}{dt}}={\vec {u}}_s({\vec {r}}_s,t)
\\[1.2ex]

{\vec {r}}_s(t_{0} = \tau_s)={\vec {r}}_{s0}

\end{cases}

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