...
Temperature | 293.15 K = 20 °C = 68 °F |
---|---|
Absolute pressure | 101,325 Pa = 101.325 kPa = 1 atm = 1.01325 bar = 14.6959 psi |
See also Standard Conditions (STP)
...
Temperature | 293.15 K = 20 °C = 68 °F |
---|---|
Absolute pressure | 101,325 Pa = 101.325 kPa = 1 atm = 1.01325 bar = 14.6959 psi |
See also Standard Conditions (STP)