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Integral formDifferential form
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\frac{d}{dt} \iiint_\Omega \rho \, dV = \dot m = \frac{dm_\Omega}{dt}
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\frac{\partial \rho}{\partial t} + \nabla (\rho \, {\bf u}) =   \frac{dm (t, {\bf r})}{dt}

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bodyt

time

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body--uriencoded--%7B\bf r %7D

position vector

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body\Omega

space volume (could be finite or infinite)

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body--uriencoded--\rho(t, %7B\bf r%7D)

continuum body spatial density distribution

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body--uriencoded--%7B\bf u%7D(t, %7B\bf r)

continuum body spatial velocity distribution

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body--uriencoded--\displaystyle \frac%7Bdm_\Omega%7D%7Bdt%7D

mass generation rate with the space volume 

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body\Omega

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body--uriencoded--\dot m = \frac%7Bdm%7D%7Bdt%7D\displaystyle \frac%7Bdm(t, %7B\bf r%7D)%7D%7Bdt%7D

mass generation rate

at a given point in space

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body--uriencoded--%7B\bf r %7D


For the specific case of stationary process when density is not explicitly dependent on timeFor the stationary fluid flow:

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\frac{\partial \rho}{\partial t} = 0 \rightarrow  \nabla (\rho \, {\bf u}) = 0

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