Recovery Pace = τ

(1)	$\begin{array}{l}\displaystyle \tau(t) = - \frac{dQ}{dq} =-\frac{1}{q} \cdot \frac{dq}{dt} = - \frac{d (\ln q)}{dt}\end{array}$

It is inverse value to Production Decrement $\begin{array}{l}D(t)\end{array}$ :

(2)	$\begin{array}{l}\displaystyle \tau(t) = \frac{1}{D(t)}\end{array}$

In case of Exponential Production Decline the Recovery Pace is constant in time: $\begin{array}{l}\tau(t) = \tau_0 = \rm const\end{array}$ .

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