changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Nov 09, 2021
Saved on Nov 27, 2021
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\frac{d Q^{\downarrow}_{AQ}}{dt} + \frac{1}{\tau} Q^{\downarrow}_{AQ} = B_w \, Jс_t \, V_\phi \cdot ( p_i - p(t))
q^{\downarrow}_{AQ}(t)=\frac{d Q^{\downarrow}_{AQ}}{dt}