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\ln {\mu}_{12} = x_1 \cdot \ln {\mu}_1 +  x_2  \cdot \ln {\mu}_2 

\ln {\mu}_{12} = \frac{x_1}{x_1 + \alpha \, x_2} \cdot \ln {\mu}_1 +  \frac{\alpha \, x_2}{x_1 + \alpha \,x_2}  \cdot \ln {\mu}_2 

\ln {\mu}_{12} = x_1 \cdot \ln {\mu}_1 + x_2 \cdot \ln {\mu}_2 + \epsilon \, x_1 \, x_2

\ln {\mu}_{12} = x_1 \cdot \ln {\mu}_1 + x_2 \cdot \ln {\mu}_2 + \epsilon \, x_1 \, x_2 + K_1 \, x_1 \, x_2 \, (x_1 - x_2) + K_2 \, x_1 \, x_2 \, (x_1 - x_2)^2

{\nu}_{12}^{1/3} = \left[ x_1 \cdot \nu_1^{1/3} + x_2 \cdot \nu_2^{1/3} \right]^3

{\nu}_{12} = \exp \left[ \, \exp \left(\frac{A_{12}-10.975}{14.534} \right) - 0.8 \, \right], \ \ A_{12} = y_1 \, A_1 + y_2 \, A_2, \ \ A_i = 14.534 \, \ln \left[ \,
\ln \left( \nu_i + 0.8
\right) \,
\right] + 10.975, \ \ i = \{ 1,2\}