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-\frac{1}{c} \frac{d}{dl} \left( \frac{1}{\rho} \right) = g \frac{dz}{dl} -+ \frac{\rho_s^2 q_s^2}{2A^2} \frac{d}{dl} \left( \frac{1}{\rho^2} \right) -+ \frac{\rho_s^2 q_s^2}{2A^2} \frac{f}{d} \left( \frac{1}{\rho^2} \right) - g \frac{dz}{dl} = 0 |
See Derivation of Pressure Profile in Stationary Isothermal Homogenous Pipe Flow @model.
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