changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Nov 27, 2021
Saved on Nov 28, 2021
...
\tau \cdot \frac{d Q^{\downarrow}_{AQ}}{dt} + \frac{1}{\tau} Q^{\downarrow}_{AQ} = с_t \, V_\phi \cdot \left[ p_i - p(t) \right]
q^{\downarrow}_{AQ}(t)=\frac{d Q^{\downarrow}_{AQ}}{dt}
