changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Feb 07, 2019
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q^{\downarrow}_{AQ}(t)= J \cdot \frac{\partial p_a}{\partial r}
\frac{\partial p_1}{\partial t_D} = \frac{\partial^2 p_1}{\partial r_D^2} + \frac{1}{r_D}\cdot \frac{\partial p_1}{\partial r_D}
\frac{d Q^{\downarrow}_{AQ}}{dt} = q^{\downarrow}_{AQ}(t)
p_1(t = 0, r)= 0
p_a(t, r)= p(0) + \int_0^t p_1(t-\tau) \dot p(\tau) d\tau
p_1(t, r=r_e)} = 1
\frac{\partial p_1}{\partial r_D}(t, r=r_a) = 0