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\frac{D \rho}{ Dt} = \frac{\partial \rho}{\partial t} + \rho \cdot \nabla {\bf u} = 0



This also implies that material balance equation:

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\frac{\partial \rho}{\partial t} + \nabla (\rho \, {\bf u}) = 0

simplifies to:

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 \nabla {\bf u} = 0


It does not necessarily means that the fluid itself is incompressible

See also

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Physics / Mechanics / Continuum mechanics / Fluid Mechanics / Fluid Dynamic

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