changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Oct 28, 2018
...
LaTeX Math Inlinebodyb=1
LaTeX Math Inlinebodyb=0
LaTeX Math Inlinebody0<b<1
q(t)=q_{i} \exp \left( -D \, t \right)
q(t)=\frac{q_{i}}{1+D \, t}
q(t)=q_{i} \cdot \left( 1+b \cdot D \cdot t \right)^{-1/b}
q(t)=q_{i} \exp \left( -D_{\infty}t- \left( t/\tau \right)^{n} \right)
Q(t)=\frac{q_{i}-q(t)}{D}
Q(t)=\frac{q_{i}}{D} \, \ln \left[ \frac{q_{i}}{q(t)} \right]
Q(t)=\frac{q_{i}}{D \, (1-b)} \, \left[ q_{i}^{1-b}-q(t)^{1-b} \right]