changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Oct 27, 2018
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q(t)=q_{i} \exp \big [ -D \, t \big ]
q(t)=\frac{q_{i}}{[1+D \, t]}
q(t)=\frac{q_{i}}{[1+b \, D \, t]^{\frac{1}{b}}}
q(t)=q_{i} \exp \big [ -D_{\infty}t- \bigg(\frac{t}{\tau} \bigg)^{n} \big]
Q(t)=\frac{q_{i}-q(t)}{D}
Q(t)=\frac{q_{i}}{D}\ln (\frac{q_{i}}{q(t)})
Q(t)=\frac{q_{i}}{D \, (1-b)}(q_{i}^{1-b}-q(t)^{1-b})