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LaTeX Math Block
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\tau(t) = \frac{1}{D(t)} = - \frac{dQ}{dq} = - \left[ \frac{d \ln q}{dt} \right]^{-1}  \quad \rightarrow  \quad  \tau(t) = \tau_0 + b\cdot t = \frac{1}{D_0} + b\cdot t

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