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D(t) = - \frac{dq}{dQ} = - \frac{d \, \ln q(t)}{dt} = \frac{D_0}{1+ b \cdot D_0 \cdot t} |
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| LaTeX Math Block | ||||
|---|---|---|---|---|
| ||||
D(t) = - \frac{dq}{dQ} = - \frac{d \, \ln q(t)}{dt} = \frac{D_0}{1+ b \cdot D_0 \cdot t} |
...