changes.mady.by.user Arthur Aslanyan (Nafta College)
Saved on Sep 07, 2022
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LaTeX Math Inlinebodyb=0
LaTeX Math Inlinebody0<b<1
LaTeX Math Inlinebodyb=1
q(t)=q_0 \exp \left( -D_0 \, t \right)
q(t) = \frac{q_0}{ \left( 1+b \cdot D_0 \cdot t \right)^{1/b} }
q(t)=\frac{q_0}{1+D_0 \, t}
Q(t)=\frac{q_0-q(t)}{D_0}
Q(t)=\frac{q_0}{D_0 \, (1-b)} \, \left[ 1- \left( \frac{q(t)}{q_0} \right)^{1-b} \right]
Q(t)=\frac{q_0}{D_0} \, \ln \left[ \frac{q_0}{q(t)} \right]
Q_{\rm max}=\frac{q_0}{D_0}
Q_{\rm max}=\frac{q_0}{D_0 \cdot (1-b)}
Q_{\rm max}=\infty
D(t) = D_0 = \rm const
D(t) =\frac{D_0}{1+ b \cdot D_0 \cdot t}
D(t) = \frac{D_0}{1+ D_0 \cdot t}
\tau(t) = \tau_0 = \rm const
\tau(t) = \tau_0 + b \cdot t
\tau(t) = \tau_0 + t
\mathrm{RPR}(t) = \tau(t) = \tau_0 = \rm const
\mathrm{RPR}(t) = \tau_0 \, \left[ 1 + \frac{q_0 \, b }{(1-b)} \cdot \frac{1q_0}{q(t)} \right]
\mathrm{RPR}(t) = \rm{not applicable due to infinite volume}