Normalised measure of the total amount $\begin{array}{l}N\end{array}$ of the constitutive particles (molecules/atoms) in a given sample of substance:

(1)	$\begin{array}{l}\displaystyle \nu = \frac{N}{N_A}\end{array}$

where

$\begin{array}{l}N_A\end{array}$ = 6.022140758(62) · 10²³ mol⁻¹

Symbol	Dimension	SI Unit	Oil Metric Unit	Oil Field Unit
$\begin{array}{l}\nu\end{array}$	1	mol	mol	mol

Alternative equations:

  
	(2)
	\nu = \frac{m}{M}

  
	(3)
	\nu = \frac{V}{V_m}

$\begin{array}{l}m\end{array}$

mass of a substance with amount $\begin{array}{l}\nu\end{array}$

$\begin{array}{l}V\end{array}$

$\begin{array}{l}M\end{array}$

$\begin{array}{l}V_m\end{array}$

Derivation

$\begin{array}{l}\displaystyle \nu = \frac{N}{N_A} = \frac{ m_u \cdot N }{m_u \cdot N_A} = \frac{m}{M}\end{array}$

where

$\begin{array}{l}m_u\end{array}$

Derivation

$\begin{array}{l}\displaystyle \nu = \frac{m}{M} = \frac{\rho \cdot V}{M} = \frac{V}{V_m}\end{array}$

where

$\begin{array}{l}\rho\end{array}$

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