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LaTeX Math Block
alignmentleft
\begin{cases}


\displaystyle 


{\frac {d{\vec {xr}}_{P}}s(t)}{dt}}(t)={\vec {u}}_{P}s({\vec {xr}}_{P}(t)s,t)
\\[1.2ex]

{\vec {xr}}_{P}s(t_{0})={\vec {xr}}_{P0s0}

\end{cases}